How many grams of concentrated nitric acid so | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Step $1$: Calculate the number of moles of $HNO_3$ required.$n = M 	imes V(L) = 2.0 \ mol/L 	imes 0.250 \ L = 0.5 \ mol$.Step $2$: Calculate the

Vedclass · Accepted Answer

$45.0 \ g$ conc. $HNO_3$

Vedclass · Answer

(C) Step $1$: Calculate the number of moles of $HNO_3$ required.$n = M 	imes V(L) = 2.0 \ mol/L 	imes 0.250 \ L = 0.5 \ mol$.Step $2$: Calculate the mass of pure $HNO_3$ required.Molar mass of $HNO_3 = 1 + 14 + (3 	imes 16) = 63 \ g/mol$.Mass of $HNO_3 = 0.5 \ mol 	imes 63 \ g/mol = 31.5 \ g$.Step $3$: Calculate the mass of the $70\%$ concentrated solution.Since the solution is $70\%$ $HNO_3$ by mass,$70 \ g$ of $HNO_3$ is present in $100 \ g$ of solution.Mass of solution $= (100 \ g 	ext{ solution} / 70 \ g 	ext{ } HNO_3) 	imes 31.5 \ g 	ext{ } HNO_3 = 45 \ g$.

How many grams of concentrated nitric acid solution should be used to prepare $250 \ mL$ of $2.0 \ M \ HNO_3$? The concentrated acid is $70\% \ HNO_3$ by mass.

Similar Questions

At $300 \ K$ and $1 \ \text{atm}$ pressure,$10 \ mL$ of a hydrocarbon required $55 \ mL$ of $O_2$ for complete combustion,and $40 \ mL$ of $CO_2$ is formed. The formula of the hydrocarbon is

$0.43 \ g$ of a metal of valence $2$ was dissolved in $50 \ mL$ of $0.5 \ M \ H_2SO_4$ solution. The unreacted acid required $14.2 \ mL$ of $1 \ M \ NaOH$ solution for neutralization. The atomic weight of the metal is: (in $u$)

$X$ litre of carbon monoxide is present at $STP$. It is completely oxidized to $CO_2$. The volume of $CO_2$ formed is $11.207 \ L$. What is the value of $X$ in litres?

$6.023 \times 10^{22}$ molecules are present in $10 \ g$ of a substance $'x'.$ The molarity of a solution containing $5 \ g$ of substance $'x'$ in $2 \ L$ solution is.......... $\times 10^{-3}$

What is the amount of water formed by combustion of $1.6 \ g$ methane (in $g$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module