How many geometrical isomers are possible for | vedclass

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Question

(B) The compound $1,2$-dimethylcyclohexane exhibits geometrical isomerism due to the restricted rotation around the $C-C$ bond in the cyclohexane ring

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The compound $1,2$-dimethylcyclohexane exhibits geometrical isomerism due to the restricted rotation around the $C-C$ bond in the cyclohexane ring.There are two geometrical isomers possible for this compound:$1$. $cis$-$1,2$-dimethylcyclohexane: Both methyl groups are on the same side of the ring.$2$. $trans$-$1,2$-dimethylcyclohexane: The methyl groups are on opposite sides of the ring.Therefore,the total number of geometrical isomers is $2$.

How many geometrical isomers are possible for $1,2$-dimethylcyclohexane?

Similar Questions

Which of the following can show geometrical isomerism?

Which of the following shows geometrical isomers?
$(a)$ $CH_2=CHCl$
$(b)$ $CH_3CH=CH_2$
$(c)$ $CHCl=CHCl$
$(d)$ $(CH_3)_2C=CHC_2H_5$

Which of the following compounds does not show geometrical isomerism?

Assign double bond configurations ($E$ or $Z$) to the following structure:

$CH_3 - CH = C(Br) - C(Cl) = CH - CH_3$
How many geometrical isomers are possible for this compound?

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