How many enantiomer pairs are obtained by mon | vedclass

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(A) The structure of $2, 3-$dimethylbutane is $CH_3-CH(CH_3)-CH(CH_3)-CH_3$. There are two types of equivalent hydrogens in this molecule: $1.$ Primar

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(A) The structure of $2, 3-$dimethylbutane is $CH_3-CH(CH_3)-CH(CH_3)-CH_3$. There are two types of equivalent hydrogens in this molecule: $1.$ Primary hydrogens: Monochlorination at a primary carbon gives $ClCH_2-CH(CH_3)-CH(CH_3)-CH_3$ ($1-$chloro$-2, 3-$dimethylbutane). This molecule has one chiral center at $C-2$,so it exists as one pair of enantiomers ($d$ and $l$ forms). $2.$ Tertiary hydrogens: Monochlorination at a tertiary carbon gives $CH_3-CCl(CH_3)-CH(CH_3)-CH_3$ ($2-$chloro$-2, 3-$dimethylbutane). This molecule is achiral because it does not have a chiral center. Thus,only $1$ pair of enantiomers is obtained.

How many enantiomer pairs are obtained by monochlorination of $2, 3-$dimethylbutane?

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