How many different stereoisomers are possible | vedclass

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(D) The given molecule is $pent-3-en-2-ol$,which is $CH_3-CH(OH)-CH=CH-CH_3$.This molecule has one chiral center at $C-2$ (the carbon attached to the

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$4$

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(D) The given molecule is $pent-3-en-2-ol$,which is $CH_3-CH(OH)-CH=CH-CH_3$.This molecule has one chiral center at $C-2$ (the carbon attached to the $-OH$ group).It also has a carbon-carbon double bond at $C-3$ and $C-4$,which can exhibit geometrical isomerism ($cis$ and $trans$ forms).Since there is one chiral center $(n=1)$,there are $2^1 = 2$ optical isomers ($R$ and $S$ configurations).Since there is one double bond capable of geometrical isomerism,there are $2$ geometrical isomers ($cis$ and $trans$).Total stereoisomers = (Number of optical isomers) $	imes$ (Number of geometrical isomers) = $2 	imes 2 = 4$.

List-$I$ Isomeric pairs	List-$II$ Type of isomers
$A$. Propanamine and $N$-Methylethanamine	$I$. Metamers
$B$. Hexan-$2$-one and Hexan-$3$-one	$II$. Positional isomers
$C$. Ethanamide and Hydroxyethanimine	$III$. Functional isomers
$D$. $o$-nitrophenol and $p$-nitrophenol	$IV$. Tautomers

How many different stereoisomers are possible for the given molecule $CH_3-CH(OH)-CH=CH-CH_3$?

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