How many carbon atoms does an alkane (not a c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For an alkane to exist in an enantiomeric form,it must possess at least one chiral carbon atom (a carbon atom bonded to four different groups).Let

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(D) For an alkane to exist in an enantiomeric form,it must possess at least one chiral carbon atom (a carbon atom bonded to four different groups).Let the chiral carbon be $C^*$. The four groups attached to $C^*$ must be different.In an alkane,the smallest groups are hydrogen $(-H)$,methyl $(-CH_3)$,ethyl $(-CH_2CH_3)$,and propyl $(-CH_2CH_2CH_3)$.Summing the carbon atoms in these groups: $1$ (for the chiral carbon) $+ 1$ (methyl) $+ 2$ (ethyl) $+ 3$ (propyl) $= 7$ carbon atoms.Therefore,the smallest alkane capable of exhibiting enantiomerism is $3$-methylhexane,which has $7$ carbon atoms.

How many carbon atoms does an alkane (not a cycloalkane) need before it is capable of existing in an enantiomeric form?

Similar Questions

Ethyl iodide and $n$-propyl iodide are allowed to undergo Wurtz reaction. The alkane which will not be obtained in this reaction is

$CH_4$ gas is obtained in :-
$(a)$ Hydrolysis of $Al_4C_3$
$(b)$ Hydrolysis of $Be_2C$
$(c)$ Hydrolysis of $Mg_2C_3$
$(d)$ Hydrolysis of $CaC_2$

The molecular mass of a hydrocarbon is $86 \ g/mol$. What is the number of its possible structural isomers?

Which alkane is secreted by cockroaches to attract the opposite gender of its species?

What are $Y$ and $Z$ in the following reaction sequence?

Vedclass Test Series

Exam Paper Generator

Online Exam Module