How many S-S bonds,S-O-S bonds,sigma bonds,an | vedclass

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(B) The trimer of $SO_3$ is $(SO_3)_3$,which is cyclic $S_3O_9$.In this structure,there are $3$ $S-O-S$ linkages forming the ring.There are no $S-S$ b

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$0, 3, 12, 6$

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(B) The trimer of $SO_3$ is $(SO_3)_3$,which is cyclic $S_3O_9$.In this structure,there are $3$ $S-O-S$ linkages forming the ring.There are no $S-S$ bonds.Each $S$ atom is bonded to two terminal $O$ atoms via double bonds $(S=O)$ and two bridging $O$ atoms via single bonds $(S-O-S)$.Total $\sigma$ bonds: $3$ ($S-O-S$ ring) + $6$ ($S=O$ double bonds) + $6$ ($S-O$ single bonds) = $15$ $\sigma$ bonds. Wait,let's recount: There are $3$ $S-O-S$ linkages (each has $2$ $\sigma$ bonds,total $6$ $\sigma$ bonds). Each $S$ atom has $2$ terminal $O$ atoms,each with $1$ $\sigma$ and $1$ $\pi$ bond. So $3$ $S$ atoms $	imes$ $2$ terminal $O$ atoms = $6$ $\sigma$ bonds and $6$ $\pi$ bonds. Total $\sigma$ bonds = $6$ (ring) + $6$ (terminal) = $12$. Total $\pi$ bonds = $6$.Thus,the counts are: $S-S$ bonds = $0$,$S-O-S$ bonds = $3$,$\sigma$ bonds = $12$,$\pi$ bonds = $6$.

Column $I$ (Molecules)	Column $II$ (Number of lone pairs on central atom)
$A. \ NH_3$	$1. \ \text{Two}$
$B. \ H_2O$	$2. \ \text{Three}$
$C. \ XeF_2$	$3. \ \text{Zero}$
$D. \ CH_4$	$4. \ \text{Four}$
	$5. \ \text{One}$

How many $S-S$ bonds,$S-O-S$ bonds,$\sigma$ bonds,and $\pi$ bonds are present in the trimer of $SO_3$?

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