How is it convenient to obtain an image by a lens practically?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) To find the image of an object by a lens,we can in principle,take any two rays emanating from a point on an object; trace their paths using the laws of refraction and find the point where the refracted rays meet (or appear to meet). In practice,however,it is convenient to choose any two of the following rays:
$(i)$ $A$ ray emanating from the object parallel to the principal axis of the lens after refraction passes through the second principal focus $F^{\prime}$ (in a convex lens) or appears to diverge (in a concave lens) from the first principal focus $F$.
$(ii)$ $A$ ray of light,passing through the optical centre of the lens,emerges without any deviation after refraction.
$(iii)$ $A$ ray of light passing through the first principal focus (for a convex lens) or appearing to meet at it (for a concave lens) emerges parallel to the principal axis after refraction.
It must be remembered that each point on an object gives out an infinite number of rays. All these rays will pass through the same image point after refraction at the lens.

Explore More

Similar Questions

If in a plano-convex lens,the radius of curvature of the convex surface is $10 \,cm$ and the focal length of the lens is $30 \,cm$,the refractive index of the material of the lens will be ..........

$A$ biconvex lens has a radius of curvature of magnitude $20\, cm$. Which one of the following options best describes the image formed of an object of height $2\, cm$ placed $30\, cm$ from the lens?

$A$ point object $O$ is placed on the principal axis of a convex lens of focal length $20 \, cm$ at a distance of $40 \, cm$ to the left of it. The diameter of the lens is $10 \, cm$. If the eye is placed $60 \, cm$ to the right of the lens at a distance $h$ below the principal axis,then the maximum value of $h$ to see the image will be.......$cm$.

Difficult
View Solution

If the aperture of a lens is halved,then the image will be:

An extended object is placed at point $O$,$10 \ cm$ in front of a convex lens $L_1$ and a concave lens $L_2$ is placed $10 \ cm$ behind it,as shown in the figure. The radii of curvature of all the curved surfaces in both the lenses are $20 \ cm$. The refractive index of both the lenses is $1.5$. The total magnification of this lens system is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo