How does ammonia react with a solution of $Cu^{2+}$?
- AIt forms a white precipitate of $Cu(OH)_2$.
- BIt forms a deep blue complex $[Cu(NH_3)_4]^{2+}$.
- CIt reduces $Cu^{2+}$ to $Cu^+$.
- DIt forms a brown precipitate of $Cu_2O$.
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The brown ring test for $NO_2^-$ and $NO_3^-$ ions is due to the formation of which of the following complex ions?
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View SolutionWhen Ethane-$1,2$-diamine is added progressively to an aqueous solution of Nickel $(II)$ chloride,the sequence of colour change observed will be :
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View Solution$Ag^{+} + NH_3 \rightleftharpoons [Ag(NH_3)]^{+}$; $k_1 = 3.5 \times 10^{-3}$
$[Ag(NH_3)]^{+} + NH_3 \rightleftharpoons [Ag(NH_3)_2]^{+}$; $k_2 = 1.7 \times 10^{-3}$
Then the formation constant of $[Ag(NH_3)_2]^{+}$ is
$[Ag(NH_3)]^{+} + NH_3 \rightleftharpoons [Ag(NH_3)_2]^{+}$; $k_2 = 1.7 \times 10^{-3}$
Then the formation constant of $[Ag(NH_3)_2]^{+}$ is
The complex formed during the brown ring test of nitrate $(NO_3^-)$ ion is:
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View Solution$CuSO_4$ solution reacts with excess of $KCN$ solution to form:
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