How do you account for the formation of ethane during the chlorination of methane?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The chlorination of methane proceeds via a free radical mechanism involving initiation,propagation,and termination steps.
In the termination step,two methyl free radicals $(CH_3^{\bullet})$ collide and combine to form ethane $(C_2H_6)$.
$CH_3^{\bullet} + CH_3^{\bullet} \rightarrow CH_3-CH_3$

Explore More

Similar Questions

$Ph^{-}MgBr + CH_3-CH(OH)-CH_3 \to A$. What is the product $A$?

Difficult
View Solution

Which of the following will not give one monochloro product?

Match the column and find the correct answer:
Column-$I$ Column-$II$
$i$. $n$-Butane $\to 2$-methylpropane $A$. Free radical substitution
$ii$. $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$ $B$. Wurtz reaction
$iii$. $R-COONa \xrightarrow{\text{soda-lime}} R-H$ $C$. Isomerism
$iv$. $R-X + Na \xrightarrow{\text{Ether}} R-R$ $D$. Decarboxylation

Briefly explain the trends in boiling point and melting point in the alkane series.

Which of the following compounds do not undergo addition reactions?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo