Homoleptic octahedral complexes of a metal io | vedclass

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Question

(A) The crystal field splitting energy $(\Delta_o)$ is inversely proportional to the wavelength of light absorbed $(\Delta_o = \frac{hc}{\lambda})$.Th

Vedclass · Accepted Answer

$L_3 < L_1 < L_2$

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(A) The crystal field splitting energy $(\Delta_o)$ is inversely proportional to the wavelength of light absorbed $(\Delta_o = \frac{hc}{\lambda})$.The order of wavelengths for the given colors is $\lambda_{blue} Thus,the energy order is $E_{blue} > E_{green} > E_{red}$.Since ligand strength is directly proportional to $\Delta_o$,the order of ligand strength is $L_2 > L_1 > L_3$ or $L_3 < L_1 < L_2$.

Homoleptic octahedral complexes of a metal ion $M^{3+}$ with three monodentate ligands $L_1, L_2$ and $L_3$ absorb wavelengths in the region of green,blue and red respectively. The increasing order of the ligand strength is:

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