Heating the acyl azide in dry toluene under r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is an intramolecular Curtius rearrangement.$1$. Upon heating,the acyl azide undergoes loss of $N_2$ to form an acyl nitrene or direct

Vedclass · Accepted Answer

Vedclass · Answer

(A) The reaction is an intramolecular Curtius rearrangement.$1$. Upon heating,the acyl azide undergoes loss of $N_2$ to form an acyl nitrene or directly rearranges to an isocyanate intermediate.$2$. The ortho-amino group then performs a nucleophilic attack on the electrophilic carbon of the isocyanate group.$3$. This cyclization results in the formation of a cyclic urea derivative,specifically $1,3$-dihydro-$2H$-benzimidazol-$2$-one.

Heating the acyl azide in dry toluene under reflux for $3$ hours gives a $90\%$ yield for a heterocyclic product. Identify the product $(A)$.

Similar Questions

An aromatic amine $(A)$ was treated with alcoholic potash and another compound $(Y)$ to form a foul-smelling gas with the formula $C_6H_5NC$. Compound $(Y)$ was formed by reacting a compound $(Z)$ with $Cl_2$ in the presence of slaked lime. The compound $(Z)$ is:

Which of the following species would not be involved in the Hoffmann rearrangement shown below?

Product $(E)$ is

Consider the following organic reaction sequence. Choose the final product $(X)$ from the following (consider the major product in all intermediate reactions).

Ethylamine can be obtained by the:

Vedclass Test Series

Exam Paper Generator

Online Exam Module