(C) When chloroform $(CHCl_3)$ is heated with an aqueous solution of sodium hydroxide $(NaOH)$,it undergoes hydrolysis. The reaction is: $CHCl_3 + 4Na

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(C) When chloroform $(CHCl_3)$ is heated with an aqueous solution of sodium hydroxide $(NaOH)$,it undergoes hydrolysis. The reaction is: $CHCl_3 + 4NaOH \rightarrow HCOONa + 3NaCl + 2H_2O$. The product formed is sodium formate $(HCOONa)$.

Class 12 Chemistry 8-2.Carboxylic acids and Their derivative Properties of Carboxylic Acids and Their Derivatives

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Heating chloroform with aqueous sodium hydroxide solution forms:

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A
sodium acetate
B
sodium oxalate
C
sodium formate
D
chloral

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8-2.Carboxylic acids and Their derivative

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Properties of Carboxylic Acids and Their Derivatives

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Heating chloroform with aqueous sodium hydroxide solution forms:

Similar Questions

$HOOC-(CH_2)_n-COOH \xrightarrow[\Delta]{} \text{product}$At what value of $(n)$ will the given compound not evolve $CO_2$ gas?

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$HOOC-(CH_2)_n-COOH \xrightarrow[\Delta]{} \text{product}$
At what value of $(n)$ will the given compound not evolve $CO_2$ gas?

Rearrange the following in the increasing order of acidic strength:
$(i)$ benzoic acid $(ii)$ $p$-methoxybenzoic acid $(iii)$ $o$-methoxybenzoic acid