The heat required to convert $1 \, g$ of ice at $0^{\circ}C$ into steam at $100^{\circ}C$ is (given $L_{f} = 80 \, cal/g$,$c_{w} = 1 \, cal/g^{\circ}C$,$L_{v} = 536 \, cal/g$):

  • A
    $100 \, calorie$
  • B
    $0.01 \, kilocalorie$
  • C
    $716 \, calorie$
  • D
    $1 \, kilocalorie$

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