Heat energy is incident on the surface at the | vedclass

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(B) The total incident energy per unit time is $Q_{in} = 1000 ~J/min$. According to the law of conservation of energy,the sum of the coefficients of a

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$500$

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(B) The total incident energy per unit time is $Q_{in} = 1000 ~J/min$. According to the law of conservation of energy,the sum of the coefficients of absorption $(a)$,reflection $(r)$,and transmission $(t)$ is equal to $1$: $a + r + t = 1$ Given $a = 0.8$ and $r = 0.1$,we can find the coefficient of transmission $(t)$: $0.8 + 0.1 + t = 1$ $0.9 + t = 1$ $t = 0.1$ Now,the rate of heat energy transmitted is $H = t 	imes Q_{in} = 0.1 	imes 1000 = 100 ~J/min$. The total heat energy transmitted in $5$ minutes is $E = H 	imes 5 = 100 	imes 5 = 500 ~J$.

Heat energy is incident on the surface at the rate of $1000 ~J/min$. If the coefficient of absorption is $0.8$ and the coefficient of reflection is $0.1$,then the heat energy transmitted by the surface in $5$ minutes is: (in $~J$)

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