he power dissipated in the circuit shown in t | vedclass

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Question

The equivalent resistance of the given circuit is

$R_{\mathrm{eq}}=\frac{5 \,R}{5+R}$

Power dissipated in the given circuit is

${P=\frac{V^{2

Vedclass · Accepted Answer

$10$

Vedclass · Answer

The equivalent resistance of the given circuit is

$R_{\mathrm{eq}}=\frac{5 \,R}{5+R}$

Power dissipated in the given circuit is

${P=\frac{V^{2}}{R_{\mathrm{eq}}} 	ext { or } 30=\frac{(10)^{2}}{\left(\frac{5\, R}{5+R}ight)}} $

${150\, R=100(5+R)}$

${150\, R=500+100\, R \quad 	ext { or } 50\, R=500} $

${R=\frac{500}{50}=10\, \Omega}$

he power dissipated in the circuit shown in the figure is $30\,W$. The value of $R$ is ............. $\Omega$

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