Harpreet tosses two different coins simultane | vedclass

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(C) We write $H$ for 'head' and $T$ for 'tail'. When two coins are tossed simultaneously,the possible outcomes are $(H, H), (H, T), (T, H), (T, T)$,wh

Vedclass · Accepted Answer

$3/4$

Vedclass · Answer

(C) We write $H$ for 'head' and $T$ for 'tail'. When two coins are tossed simultaneously,the possible outcomes are $(H, H), (H, T), (T, H), (T, T)$,which are all equally likely.Here $(H, H)$ means head up on the first coin (say on $Rs. 1$) and head up on the second coin (say on $Rs. 2$). Similarly,$(H, T)$ means head up on the first coin and tail up on the second coin,and so on.The outcomes favourable to the event $E$,'at least one head',are $(H, H), (H, T)$,and $(T, H)$.So,the number of outcomes favourable to $E$ is $3$.The total number of possible outcomes is $4$.Therefore,$P(E) = \frac{	ext{Number of favourable outcomes}}{	ext{Total number of possible outcomes}} = \frac{3}{4}$.i.e.,the probability that Harpreet gets at least one head is $3/4$.

Harpreet tosses two different coins simultaneously (say,one is of $Rs. 1$ and other of $Rs. 2$). What is the probability that she gets at least one head?

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