Hardness of water is 200 ppm. Calculate the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $200 \ ppm$ means $200 \ g$ of $CaCO_3$ in $10^6 \ g$ (or approximately $10^6 \ mL$) of water.$	ext{Molar mass of } CaCO_3 = 40 + 12 + (3 	imes

Vedclass · Accepted Answer

$2 	imes 10^{-3} \ M ; 4 	imes 10^{-3} \ N$

Vedclass · Answer

(A) $200 \ ppm$ means $200 \ g$ of $CaCO_3$ in $10^6 \ g$ (or approximately $10^6 \ mL$) of water.$	ext{Molar mass of } CaCO_3 = 40 + 12 + (3 	imes 16) = 100 \ g/mol$.$	ext{Molarity} = \frac{	ext{mass in } g}{	ext{Molar mass}} 	imes \frac{1000}{V_{mL}} = \frac{200}{100} 	imes \frac{1000}{10^6} = 2 	imes 10^{-3} \ M$.$	ext{Equivalent mass of } CaCO_3 = \frac{	ext{Molar mass}}{n	ext{-factor}} = \frac{100}{2} = 50 \ g/eq$.$	ext{Normality} = \frac{	ext{mass in } g}{	ext{Equivalent mass}} 	imes \frac{1000}{V_{mL}} = \frac{200}{50} 	imes \frac{1000}{10^6} = 4 	imes 10^{-3} \ N$.

Hardness of water is $200 \ ppm$. Calculate the molarity and normality of $CaCO_3$ in the water.

Similar Questions

$X \ g$ of benzoic acid on reaction with aqueous $NaHCO_3$ releases $CO_2$ that occupies $11.2 \ L$ volume at $STP$. The value of $X$ is . . . . . . $g$.

What fraction of $Fe$ exists as $Fe(III)$ in $Fe_{0.96}O$?
(Consider $Fe_{0.96}$ to be made up of $Fe(II)$ and $Fe(III)$ only)

The molarity of $2 \, N \, HCl$ is .......

In an aqueous solution of $A_2B_3$,it undergoes complete ionization according to the reaction $A_2B_3 \rightleftharpoons 2A^{+3} + 3B^{-2}$. The concentration of $A^{+3}$ is equal to......

The composition of a sample of wustite is $Fe_{0.93} O_{1.00}$. The percentage of iron in the form of $Fe^{3+}$ ion is nearly:

Vedclass Test Series

Exam Paper Generator

Online Exam Module