A haemophilic man marries a normal woman. The | vedclass

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(B) Haemophilia is an $X$-linked recessive disorder. The genotype of a haemophilic man is $X^hY$ and that of a normal woman is $XX$.When they cross,th

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(B) Haemophilia is an $X$-linked recessive disorder. The genotype of a haemophilic man is $X^hY$ and that of a normal woman is $XX$.When they cross,the possible genotypes of the offspring are:$X^hY 	imes XX ightarrow X^hX, X^hX, XY, XY$Here,$X^hX$ represents carrier daughters and $XY$ represents normal sons.Since none of the offspring express the disease (as daughters are only carriers and sons are normal),all offspring are phenotypically normal.

Column-$I$	Column-$II$
$(P)$ Haemophilia	$(i)$ Recessive gene: $X^{h}X^{h}$
$(Q)$ Colour blindness	$(ii)$ Recessive gene: $pp$
$(R)$ Phenylketonuria	$(iii)$ Recessive gene: $Hb^{s}Hb^{s}$
$(S)$ Sickle-cell anaemia	$(iv)$ Recessive gene: $X^{c}X^{c}$

$A$ haemophilic man marries a normal woman. Their offspring will be:

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