Gravitational force on the surface of the moo | vedclass

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Question

(C) Weight of an object on the Earth is calculated as: $W_e = m 	imes g$,where $m = 10\, kg$ and $g = 9.8\, m/s^2$.So,$W_e = 10\, kg 	imes 9.8\, m/s

Vedclass · Accepted Answer

$16.3\, N, 98\, N$

Vedclass · Answer

(C) Weight of an object on the Earth is calculated as: $W_e = m 	imes g$,where $m = 10\, kg$ and $g = 9.8\, m/s^2$.So,$W_e = 10\, kg 	imes 9.8\, m/s^2 = 98\, N$.The gravitational force on the moon is $\frac{1}{6}$ of that on the Earth.Therefore,the weight of the object on the moon is: $W_m = \frac{1}{6} 	imes W_e$.$W_m = \frac{1}{6} 	imes 98\, N \approx 16.3\, N$.Thus,the weight on the moon is $16.3\, N$ and the weight on the Earth is $98\, N$.

Gravitational force on the surface of the moon is only $\frac{1}{6}$ as strong as the gravitational force on the earth. What is the weight in newtons of a $10\, kg$ object on the moon and on the earth?

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