Grapes are placed in three beakers X,Y,and Z | vedclass

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Question

(A) In beaker $X$,the grape remains the same size,indicating an isotonic solution where the net flow of water is zero.In beaker $Y$,the grape swells,w

Vedclass · Accepted Answer

$Y -$ hypotonic solution,$Z -$ hypertonic solution

Vedclass · Answer

(A) In beaker $X$,the grape remains the same size,indicating an isotonic solution where the net flow of water is zero.In beaker $Y$,the grape swells,which indicates that water has entered the grape due to osmosis. This happens when the surrounding solution is hypotonic (lower osmotic pressure) compared to the grape's internal solution.In beaker $Z$,the grape shrinks,which indicates that water has left the grape due to osmosis. This happens when the surrounding solution is hypertonic (higher osmotic pressure) compared to the grape's internal solution.Therefore,$Y$ is a hypotonic solution and $Z$ is a hypertonic solution.

Grapes are placed in three beakers $X$,$Y$,and $Z$ containing different types of solutions. If beaker $X$ contains an isotonic solution with the grape solution,what will be the nature of the solutions in $Y$ and $Z$?

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