The government has divided the frequency rang | vedclass

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(B) The total frequency range available is $60\ MHz - 30\ MHz = 30\ MHz$.There are $20$ stations sharing this range.Therefore,the bandwidth available

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Music signals and voice signals only

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(B) The total frequency range available is $60\ MHz - 30\ MHz = 30\ MHz$.There are $20$ stations sharing this range.Therefore,the bandwidth available for each station is $\Delta f = \frac{30\ MHz}{20} = 1.5\ MHz$.Voice signals typically require a bandwidth of $3\ kHz$,and music signals require about $15\ kHz$.$TV$ signals require a bandwidth of $6\ MHz$ for transmission.Since each station has a bandwidth of $1.5\ MHz$,it can accommodate voice signals $(3\ kHz)$ and music signals $(15\ kHz)$,but it cannot accommodate a standard $TV$ signal $(6\ MHz)$.Thus,each station can beam voice and music signals.

List $I$	List $II$
$A$. Attenuation	$I$. Combination of a receiver and transmitter.
$B$. Transducer	$II$. Process of retrieval of information from the carrier wave at receiver.
$C$. Demodulation	$III$. Converts one form of energy into another.
$D$. Repeater	$IV$. Loss of strength of a signal while propagating through a medium.

The government has divided the frequency range from $30\ MHz$ to $60\ MHz$ between $20$ stations,which are independently beaming their signals. Which of the signals can be beamed by each of the stations?

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