Glucose gives a silver mirror with ammoniacal | vedclass

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Question

(A) Glucose gives a silver mirror test (Tollens' test) with ammoniacal silver nitrate because of the presence of the $-CHO$ group (aldehyde group) in

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Aldehyde group

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(A) Glucose gives a silver mirror test (Tollens' test) with ammoniacal silver nitrate because of the presence of the $-CHO$ group (aldehyde group) in its open-chain structure.The reaction is as follows:$CH_2OH(CHOH)_4CHO + Ag_2O \rightarrow CH_2OH(CHOH)_4COOH + 2Ag \downarrow$ (silver mirror)Here,the aldehyde group is oxidized to a carboxylic acid group,and silver ions are reduced to metallic silver,forming the silver mirror.

Glucose gives a silver mirror with ammoniacal silver nitrate because it has:

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