Glucose and gluconic acid on oxidation with d | vedclass

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Question

(C) Glucose $(CHO-(CHOH)_4-CH_2OH)$ and gluconic acid $(COOH-(CHOH)_4-CH_2OH)$ both undergo oxidation with dilute $HNO_3$ to form saccharic acid $(COO

Vedclass · Accepted Answer

one primary alcoholic group

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(C) Glucose $(CHO-(CHOH)_4-CH_2OH)$ and gluconic acid $(COOH-(CHOH)_4-CH_2OH)$ both undergo oxidation with dilute $HNO_3$ to form saccharic acid $(COOH-(CHOH)_4-COOH)$.In this reaction,the terminal primary alcoholic group $(-CH_2OH)$ is oxidized to a carboxylic acid group $(-COOH)$.Since only one $-CH_2OH$ group is present in the glucose molecule and it gets converted to $-COOH$,this reaction confirms the presence of one primary alcoholic group in glucose.

Glucose and gluconic acid on oxidation with dilute nitric acid $(HNO_3)$ form saccharic acid. This reaction confirms that glucose contains:

Similar Questions

Which of the following is a reducing sugar?

Consider the following statements:
Statement-$I$: Cane sugar is a disaccharide of $\alpha-D$-glucose and $\beta-D$-fructose.
Statement-$II$: Milk sugar is a disaccharide of $\beta-D$-glucose and $\beta-D$-galactose.
The correct answer is:

On hydrolysis,sucrose gives:

Which among the following reagents is used to obtain gluconic acid from glucose?

Sucrose on hydrolysis gives

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