Difficult
Given below is an expression for the rate constant of a first order reaction occurring at a certain temperature,$T (\text{K})$.
$\ln k = 14.34 - \frac{1.25 \times 10^4}{T}$
The energy of activation in $\text{kcal mol}^{-1}$ for the reaction is :
(Given : $k$ is $\text{s}^{-1}$,$R = 1.987 \text{ cal mol}^{-1} \text{ K}^{-1}$)
$\ln k = 14.34 - \frac{1.25 \times 10^4}{T}$
The energy of activation in $\text{kcal mol}^{-1}$ for the reaction is :
(Given : $k$ is $\text{s}^{-1}$,$R = 1.987 \text{ cal mol}^{-1} \text{ K}^{-1}$)
- A$12.42$
- B$18.63$
- C$14.34$
- D$24.84$
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