Given below is a pedigree chart of a family w | vedclass

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Question

(D) In the given pedigree,both parents have free earlobes (represented by open symbols),but they have children with attached earlobes (represented by

Vedclass · Accepted Answer

The parents are heterozygous

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(D) In the given pedigree,both parents have free earlobes (represented by open symbols),but they have children with attached earlobes (represented by filled symbols). Since the parents show the dominant trait (free earlobes) and produce offspring with the recessive trait (attached earlobes),both parents must carry the recessive allele. Therefore,the parents must be heterozygous $(Aa)$ for the trait. When two heterozygous parents $(Aa 	imes Aa)$ reproduce,they can produce offspring with the genotype $aa$ (attached earlobes),which explains the presence of affected children in the pedigree.

Column $I$	Column $II$
$(1)$ Albinism	$(q)$ Recessive gene represented by $cc$
$(2)$ Phenylketonuria	$(s)$ Recessive gene represented by $pp$
$(3)$ Sickle cell anaemia	$(p)$ Recessive gene represented by $Hb^sHb^s$
$(4)$ Alkaptonuria	$(r)$ Recessive gene represented by $aa$

Given below is a pedigree chart of a family with five children. It shows the inheritance of attached earlobes as opposed to the free ones. The squares represent the male individuals and circles the female individuals. Which one of the following conclusions drawn is correct?

Similar Questions

Select the correct match.

Recessive characters are expressed:

Match the columns:

Column $I$ Column $II$

$(1)$ Albinism $(q)$ Recessive gene represented by $cc$

$(2)$ Phenylketonuria $(s)$ Recessive gene represented by $pp$

$(3)$ Sickle cell anaemia $(p)$ Recessive gene represented by $Hb^sHb^s$

$(4)$ Alkaptonuria $(r)$ Recessive gene represented by $aa$

With respect to phenylketonuria,identify which statement is not correct.

Which of the following is a genetic disease?

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