Given below are two statements:Statement I: A | vedclass

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(D) Explanation :- The basicity of an amine depends on the availability of the lone pair of electrons on the nitrogen atom.In $CH_3CONH_2$ (acetamide)

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Statement $I$ is false but statement $II$ is true.

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(D) Explanation :- The basicity of an amine depends on the availability of the lone pair of electrons on the nitrogen atom.In $CH_3CONH_2$ (acetamide),the lone pair on nitrogen is involved in resonance with the highly electronegative oxygen atom $(O)$,making it significantly less basic.In $C_6H_5NH_2$ (aniline),the lone pair on nitrogen is involved in resonance with the benzene ring,which also reduces its basicity,but to a lesser extent than in acetamide.Therefore,aniline is more basic than acetamide.Statement $I$ is false.Statement $II$ is true because the lone pair of electrons on the nitrogen atom in aniline is indeed delocalised over the benzene ring due to resonance,making it less available for protonation.

Given below are two statements:
Statement $I$: Aniline is less basic than acetamide.
Statement $II$: In aniline,the lone pair of electrons on nitrogen atom is delocalised over benzene ring due to resonance and hence less available to a proton.
Choose the most appropriate option:

Similar Questions

In the following compounds,the decreasing order of basic strength will be:

The decreasing order of basicity is:
$(1) \ CH_3CONH_2$
$(2) \ CH_3CH_2NH_2$
$(3) \ PhCH_2CONH_2$

Which of the following is converted into an alcohol on treatment with $HNO_2$?

Identify the reagent $R$ used in the reaction stated below.
$C_6H_5N_2Cl + R \rightarrow C_6H_6$

$CH_3-C(=O)-NH_2 \xrightarrow[\Delta]{Br_2 + KOH} CH_3-NH_2$. Intermediates of the reaction is/are:

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Given below are two statements:Statement $I$: Aniline is less basic than acetamide.Statement $II$: In aniline,the lone pair of electrons on nitrogen atom is delocalised over benzene ring due to resonance and hence less available to a proton.Choose the most appropriate option: