Given below are two statements: One is labelled as Assertion $A$ and the other labelled as Reason $R$.
Assertion $A$: During the boiling of water having temporary hardness,$Mg(HCO_3)_2$ is converted to $MgCO_3$.
Reason $R$: The solubility product of $Mg(OH)_2$ is greater than that of $MgCO_3$.
In the light of the above statements,choose the most appropriate answer from the options given below.

  • A
    Both $A$ and $R$ are true but $R$ is not the correct explanation of $A$.
  • B
    $A$ is true but $R$ is false.
  • C
    Both $A$ and $R$ are true and $R$ is the correct explanation of $A$.
  • D
    $A$ is false but $R$ is true.

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In the following reactions,the total number of oxygen atoms in $X$ and $Y$ is $........$.
$Na_2O + H_2O \rightarrow 2 X$
$Cl_2O_7 + H_2O \rightarrow 2 Y$

Which one of the following is not a method to remove permanent hardness of water?

When chlorine water is exposed to sunlight,$O_2$ is liberated. Hence

Match the following methods for treating hardness of water with their corresponding reagents used.
List-$I$List-$II$
$A$. Treatment with washing soda$I$. $Ca(OH)_2$
$B$. Calgon's method$II$. $Na_2CO_3$
$C$. Clark's method$III$. $NaAlSiO_4$
$D$. Zeolite/permutit process$IV$. $Na_6P_6O_{18}$

The correct match is:

Match List-$I$ with List-$II$ and select the correct answer using the codes given below.
List-$I$ List-$II$
$1.$ Heavy water $(a)$ Bicarbonates of $Ca$ and $Mg$ in water
$2.$ Temporary hard water $(b)$ No foreign ions in water
$3.$ Soft water $(c)$ $D_2O$
$4.$ Permanent hard water $(d)$ Sulphates and chlorides of $Ca$ and $Mg$ in water

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