Given below are two statements. One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A :$ Activated charcoal adsorbs $SO_{2}$ more efficiently than $CH_{4}$.
Reason $R$ : Gases with lower critical temperatures are readily adsorbed by activated charcoal.
In the light of the above statements,choose the correct answer from the options given below.
Assertion $A :$ Activated charcoal adsorbs $SO_{2}$ more efficiently than $CH_{4}$.
Reason $R$ : Gases with lower critical temperatures are readily adsorbed by activated charcoal.
In the light of the above statements,choose the correct answer from the options given below.
- ABoth $A$ and $R$ are correct and $R$ is the correct explanation of $A$.
- BBoth $A$ and $R$ are correct but $R$ is $NOT$ the correct explanation of $A$.
- C$A$ is correct but $R$ is not correct.
- D$A$ is not correct but $R$ is correct.
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Similar Questions
Adsorption of a gas follows Freundlich adsorption isotherm. If $x$ is the mass of the gas adsorbed on mass $m$ of the adsorbent,the correct plot of $\frac{x}{m}$ versus $p$ is:
Assertion $(A)$: van der Waals' forces are responsible for chemisorption.
Reason $(R)$: High temperature is favourable for chemisorption.
The correct answer is
Reason $(R)$: High temperature is favourable for chemisorption.
The correct answer is
Which statements among the following are correct?
$(i)$ Freundlich isotherm fails at high pressure of the gas.
$(ii)$ $\Delta H < 0$ for both physical and chemical adsorption.
$(iii)$ Physical adsorption is non-selective.
$(iv)$ Chemical adsorption is reversible,whereas physical adsorption is irreversible.
$(i)$ Freundlich isotherm fails at high pressure of the gas.
$(ii)$ $\Delta H < 0$ for both physical and chemical adsorption.
$(iii)$ Physical adsorption is non-selective.
$(iv)$ Chemical adsorption is reversible,whereas physical adsorption is irreversible.
Adsorption is always
Easy
View SolutionWhen $O_{2}$ is adsorbed on a metallic surface,electron transfer occurs from the metal to $O_{2}$. The $TRUE$ statement$(s)$ regarding this adsorption is(are)
$(A)$ $O_{2}$ is physisorbed
$(B)$ heat is released
$(C)$ occupancy of $\pi_{2p}^{*}$ of $O_{2}$ is increased
$(D)$ bond length of $O_{2}$ is increased
$(A)$ $O_{2}$ is physisorbed
$(B)$ heat is released
$(C)$ occupancy of $\pi_{2p}^{*}$ of $O_{2}$ is increased
$(D)$ bond length of $O_{2}$ is increased
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