Given,$\sin x = \sum_{n=1}^{\infty} (-1)^{n-1} \frac{x^{2n-1}}{(2n-1)!}$. If the function $f(x)$ given by $f(x) = \frac{\cos(\sin x) - \cos x}{x^4}$ for $x \neq 0$ and $f(0) = k$ is continuous at $x = 0$,then $k =$

  • A
    $\frac{1}{6}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{1}{2}$
  • D
    $0$

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