Given $f(x) = \frac{ax + b}{x + 1}$,$\lim_{x \rightarrow \infty} f(x) = 1$ and $\lim_{x \rightarrow 0} f(x) = 2$,then $f(-2)$ is

  • A
    $0$
  • B
    $1$
  • C
    $2$
  • D
    $3$

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