Given the following structures:(I) 1,3,5-trim | vedclass

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(D) The enthalpy of hydrogenation is inversely proportional to the stability of the alkene/diene system.$(I)$ is an aromatic compound (mesitylene),whi

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$III > II > I$

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(D) The enthalpy of hydrogenation is inversely proportional to the stability of the alkene/diene system.$(I)$ is an aromatic compound (mesitylene),which is highly stable due to resonance energy.$(II)$ is a conjugated diene system with some cross-conjugation,making it less stable than the aromatic system but more stable than the isolated exocyclic double bonds.$(III)$ contains three isolated exocyclic double bonds,which are the least stable among the three.Stability order: $I > II > III$.Since enthalpy of hydrogenation is inversely proportional to stability,the order of enthalpy of hydrogenation is $III > II > I$.

Given the following structures:
$(I)$ $1,3,5-$trimethylbenzene (mesitylene)
$(II)$ $1,3-$dimethyl$-5-$methylenecyclohexa$-1,3-$diene
$(III)$ $1,3,5-$trimethylenecyclohexane
The enthalpy of hydrogenation of these compounds will be in the order as:

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Given the following structures:$(I)$ $1,3,5-$trimethylbenzene (mesitylene)$(II)$ $1,3-$dimethyl$-5-$methylenecyclohexa$-1,3-$diene$(III)$ $1,3,5-$trimethylenecyclohexaneThe enthalpy of hydrogenation of these compounds will be in the order as: