Give the structures of the products you would expect when each of the following alcohols reacts with $(a)$ $HCl - ZnCl_{2}$,$(b)$ $HBr$,and $(c)$ $SOCl_{2}$: $(i)$ $Butan-1-ol$,$(ii)$ $2-Methylbutan-2-ol$.

(N/A) $(i)$ $CH_{3}CH_{2}CH_{2}CH_{2}OH$ (Butan$-1-$ol) $\xrightarrow{HCl + ZnCl_{2}}$ No reaction at room temperature. Primary alcohols do not react with Lucas' reagent at room temperature.
$(ii)$ $CH_{3}CH_{2}C(OH)(CH_{3})_{2}$ ($2$-Methylbutan$-2-$ol,$3^{\circ}$) $\xrightarrow{HCl + ZnCl_{2}}$ $CH_{3}CH_{2}C(Cl)(CH_{3})_{2}$ ($2$-Chloro$-2-$methylbutane) + $H_{2}O$. Tertiary alcohols react immediately with Lucas' reagent to form white turbidity.
$(b)$
$(i)$ $CH_{3}CH_{2}CH_{2}CH_{2}OH + HBr \to CH_{3}CH_{2}CH_{2}CH_{2}Br$ ($1$-Bromobutane) + $H_{2}O$.
$(ii)$ $CH_{3}CH_{2}C(OH)(CH_{3})_{2} + HBr \to CH_{3}CH_{2}C(Br)(CH_{3})_{2}$ ($2$-Bromo$-2-$methylbutane) + $H_{2}O$.
$(c)$
$(i)$ $CH_{3}CH_{2}CH_{2}CH_{2}OH + SOCl_{2} \to CH_{3}CH_{2}CH_{2}CH_{2}Cl$ ($1$-Chlorobutane) + $SO_{2} + HCl$.
$(ii)$ $CH_{3}CH_{2}C(OH)(CH_{3})_{2} + SOCl_{2} \to CH_{3}CH_{2}C(Cl)(CH_{3})_{2}$ ($2$-Chloro$-2-$methylbutane) + $SO_{2} + HCl$.