Give resonance of ${{\rm{O}}_3}$, And Explain its requirement, delimitation and advantages
Resonance Structures : Different Lewis structure of single molecule / ion is known as resonance structure. According to the concept of resonance, whenever a single Lewis structure cannot describe a molecule accurately so more than one Lewis structure means resonance structure describe.
Resonance structure of ozone $\left(\mathrm{O}_{3}\right)$ : To draw resonance structure the position of nucleus of atom is not change. Every reasons structure the position of bonding and non-bonding electron is change but Lewis structure is not seen different. The different resonance structure is represented by a double headed arrow. All resonance structure are similar energy.
Two resonance structure of $\mathrm{O}_{3}$ molecule $(I)$ and $(II)$ and $(III)$ is resonance hybrid.
Limitation of resonance : Any one is not seen right structure. The $\mathrm{O}-\mathrm{O}$ bond length is 148 and $\mathrm{O}=\mathrm{O}$ bond length is $121 \mathrm{pm}$. Thus single and double bond length is not experimentally present in $\mathrm{O}_{3}$.
$\therefore$ Correct structure of $\mathrm{O}_{3}$ is not $(I)$ and $(II)$
Resonance : Correct structure is resonance hybrid. Experimentally determined oxygen - oxygen $(\mathrm{O}-\mathrm{O})$ bond length in the $\mathrm{O}_{3}$ molecule are same $128 \mathrm{pm}$. So, $(III)$ is a real or accurate structure of $\mathrm{O}_{3}$ in which single and double bond is not stable. Resonance structure are necessary because it gives correct different Lewis structure.
Orientation : Single assumption structure can't give correct bond length \& bond energy.
Advantage : It gives assumption of correct structure.
Choose the $CORRECT$ comparison of decreasing $\pi -$ bond order of $S-O$ bond ?
The number of possible resonance structures for $CO_3^{2 - }$is
Which of the following conditions is not correct for resonating structures?
Resonating structures have different
Bond length of ethane $(I),$ ethene $(II),$ acetylene $(III)$ and benzene $(IV)$ follows the order