Identify the conjugate acid-base pairs in the | vedclass

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Question

(A) conjugate acid-base pair differs by a single proton $(H^+)$.In the reaction $NH_{3(aq)} + H_2O_{(l)} \rightleftharpoons NH_{4(aq)}^+ + OH_{(aq)}^-

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$NH_3 / NH_4^+$ and $H_2O / OH^-$

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(A) conjugate acid-base pair differs by a single proton $(H^+)$.In the reaction $NH_{3(aq)} + H_2O_{(l)} \rightleftharpoons NH_{4(aq)}^+ + OH_{(aq)}^-$:$1$. $NH_3$ acts as a base and accepts a proton to form its conjugate acid $NH_4^+$. Thus,$(NH_3, NH_4^+)$ is a conjugate acid-base pair.$2$. $H_2O$ acts as an acid and donates a proton to form its conjugate base $OH^-$. Thus,$(H_2O, OH^-)$ is a conjugate acid-base pair.

Identify the conjugate acid-base pairs in the reaction: $NH_{3(aq)} + H_2O_{(l)} \rightleftharpoons NH_{4(aq)}^+ + OH_{(aq)}^-$

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