From the top of a tower,a particle is thrown vertically downwards with a velocity of $10\; m/s$. The ratio of the distances covered by it in the $3^{rd}$ and $2^{nd}$ seconds of the motion is (Take $g = 10\; m/s^2$).

  • A
    $5:7$
  • B
    $7:5$
  • C
    $3:6$
  • D
    $6:3$

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