From the photoelectric effect experiment,sele | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Einstein's photoelectric equation,$K_{max} = h
u - \Phi_0$,where $K_{max}$ is the maximum kinetic energy,$h
u$ is the energy of the

Vedclass · Accepted Answer

The saturation current increases as the intensity of incident light increases.

Vedclass · Answer

(D) According to Einstein's photoelectric equation,$K_{max} = h
u - \Phi_0$,where $K_{max}$ is the maximum kinetic energy,$h
u$ is the energy of the incident photon,and $\Phi_0$ is the work function of the metal.$1$. The wave theory of light fails to explain the photoelectric effect because it cannot account for the instantaneous emission of electrons or the existence of a threshold frequency.$2$. $K_{max}$ depends on the frequency of incident light $(u)$,not its intensity.$3$. The stopping potential $(V_s)$ is given by $eV_s = K_{max} = h
u - \Phi_0$. Thus,it depends on both the frequency of incident light and the work function of the metal.$4$. The saturation current is directly proportional to the number of photoelectrons emitted per second,which is directly proportional to the intensity of the incident light. Therefore,as intensity increases,the saturation current increases.

From the photoelectric effect experiment,select the correct statement.

Similar Questions

$A$ photocell employs the photoelectric effect to convert

The work function of a metal is

The number of photo-electrons emitted per second from a metal surface increases when:

Which one of the following is true in photoelectric emission?

The time taken by a photoelectron to come out after the photon strikes is approximately

Vedclass Test Series

Exam Paper Generator

Online Exam Module