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(C) From the graph,the amplitude $A$ is the maximum displacement from the mean position,which is $A = 0.2 \, m$.The time period $T$ is the time taken

Vedclass · Accepted Answer

$0.2\pi \, m/s$

Vedclass · Answer

(C) From the graph,the amplitude $A$ is the maximum displacement from the mean position,which is $A = 0.2 \, m$.The time period $T$ is the time taken for one complete oscillation. From the graph,one complete cycle starts at $t = 0$ and ends at $t = 2 \, s$,so $T = 2 \, s$.The angular frequency $\omega$ is given by $\omega = \frac{2\pi}{T} = \frac{2\pi}{2} = \pi \, rad/s$.The maximum velocity $V_{\max}$ of a particle in simple harmonic motion is given by $V_{\max} = A\omega$.Substituting the values,$V_{\max} = 0.2 	imes \pi = 0.2\pi \, m/s$.

From the given displacement-time graph of an oscillating particle,find the maximum velocity of the particle.

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