From the figure shown,establish a relation be | vedclass

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(B) $1$. At the first interface between medium $\mu_1$ and $\mu_3$,the light ray enters normally (perpendicular to the surface). Since the angle of in

Vedclass · Accepted Answer

$\mu_3 < \mu_2; \mu_3 = \mu_1$

Vedclass · Answer

(B) $1$. At the first interface between medium $\mu_1$ and $\mu_3$,the light ray enters normally (perpendicular to the surface). Since the angle of incidence is $0^\circ$,there is no deviation of the light ray. This implies that the refractive indices of the two media are equal,so $\mu_1 = \mu_3$.$2$. At the second interface between medium $\mu_3$ and $\mu_2$,the light ray bends towards the normal. According to Snell's law,when a light ray travels from a rarer medium to a denser medium,it bends towards the normal. Therefore,the medium $\mu_2$ must be optically denser than medium $\mu_3$,which implies $\mu_2 > \mu_3$.

From the figure shown,establish a relation between $\mu_1, \mu_2, \mu_3$.

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