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(B) Total number of cards in a pack $= 52$.Number of kings in a pack $= 4$.Number of queens in a pack $= 4$.Since the events are mutually exclusive,th

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$\frac{2}{13}$

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(B) Total number of cards in a pack $= 52$.Number of kings in a pack $= 4$.Number of queens in a pack $= 4$.Since the events are mutually exclusive,the probability of drawing a king or a queen is the sum of their individual probabilities.$P(	ext{king}) = \frac{4}{52} = \frac{1}{13}$.$P(	ext{queen}) = \frac{4}{52} = \frac{1}{13}$.$P(	ext{king or queen}) = P(	ext{king}) + P(	ext{queen}) = \frac{1}{13} + \frac{1}{13} = \frac{2}{13}$.

From a pack of $52$ cards,one card is drawn at random. The probability that it is either a king or a queen is:

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