From a pack of $52$ cards,one card is drawn at random. The probability that it is either a king or a queen is:

  • A
    $\frac{1}{13}$
  • B
    $\frac{2}{13}$
  • C
    $\frac{3}{13}$
  • D
    $\frac{4}{13}$

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Similar Questions

For two events $A$ and $B$,if $P(A \cup B) = \frac{3}{4}$,$P(A \cap B) = \frac{1}{4}$,and $P(A') = \frac{2}{3}$,then find $P(A' \cap B)$.

If $A$ and $B$ are events of a random experiment such that $P(A \cup B) = \frac{4}{5}$,$P(\bar{A} \cup \bar{B}) = \frac{7}{10}$,and $P(B) = \frac{2}{5}$,then $P(A)$ equals

If $A$ and $B$ are mutually exclusive events with $P(A)=\frac{1}{4}$ and $P(B)=\frac{3}{7}$,then what is the value of $P(A / A \cup B)$?

Let $A$ and $B$ be events in a sample space $S$ such that $P(A)=0.5, P(B)=0.4$ and $P(A \cup B)=0.6$. Observe the following lists. The correct match of List $I$ from List $II$ is:
List $I$List $II$
$(i) \ P(A \cap B)$$(1) \ 0.4$
$(ii) \ P(A \cap \bar{B})$$(2) \ 0.2$
$(iii) \ P(\bar{A} \cap B)$$(3) \ 0.3$
$(iv) \ P(\bar{A} \cap \bar{B})$$(4) \ 0.1$

Let $A = \{1, 3, 5, 7, 9\}$ and $B = \{2, 4, 6, 8\}$. If an ordered pair $(a, b)$ is chosen at random from the Cartesian product $A \times B$,what is the probability that $a + b = 9$?

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