From a circular disc of radius $R$, a square is cut out with a radius as its diagonal. The center of mass of remainder part is at a distance (from the centre)
From a circular disc of radius $R$, a square is cut out with a radius as its diagonal. The center of mass of remainder part is at a distance (from the centre)
- A
$\frac{R}{{(4\pi - 2)}}$
- B
$\frac{R}{{2\pi }}$
- C
$\frac{R}{{(\pi - 2)}}$
- D
$\frac{R}{{(2\pi - 2)}}$
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A square shaped hole of side $l=\frac{a}{2}$ is carved out at a distance $d =\frac{ a }{2}$ from the centre $'O'$ of a uniform circular disk of radius $a$. If the distance of the centre of mass of the remaining portion from $O$ is $-\frac{a}{X},$ value of $X$ (to the nearest integer) is.......
A square shaped hole of side $l=\frac{a}{2}$ is carved out at a distance $d =\frac{ a }{2}$ from the centre $'O'$ of a uniform circular disk of radius $a$. If the distance of the centre of mass of the remaining portion from $O$ is $-\frac{a}{X},$ value of $X$ (to the nearest integer) is.......
- [JEE MAIN 2020]
The centre of mass of a body
The centre of mass of a body