Four plates of the same area of cross-section | vedclass

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(B) The given arrangement consists of four parallel plates. Looking at the connections,the first and third plates are connected to terminal $A$,while

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$\frac{3{\varepsilon _0}A}{d}$

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(B) The given arrangement consists of four parallel plates. Looking at the connections,the first and third plates are connected to terminal $A$,while the second and fourth plates are connected to terminal $B$. This creates three capacitors connected in parallel between terminals $A$ and $B$. Each capacitor has a capacitance of $C = \frac{{\varepsilon _0}A}{d}$. Since they are in parallel,the equivalent capacitance is $C_{eq} = C + C + C = 3C$. Substituting the value of $C$,we get $C_{eq} = \frac{3{\varepsilon _0}A}{d}$.

Four plates of the same area of cross-section are joined as shown in the figure. The distance between each plate is $d$. The equivalent capacitance across $A$ and $B$ will be

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