Four capacitors of equal capacity have an equivalent capacitance $C_{1}$ when connected in series and an equivalent capacitance $C_{2}$ when connected in parallel. The ratio $\frac{C_{2}}{C_{1}}$ is:

Three capacitors each of capacitance $1\,\mu F$ are connected in parallel. To this combination,a fourth capacitor of capacitance $1\,\mu F$ is connected in series. The resultant capacitance of the system is.......$\mu F$

“The magnitude of effective capacitance in series connection of capacitors increases.” Is this statement true or false?

Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be

The combination of capacitors with $C_1 = 3\,\mu F$,$C_2 = 4\,\mu F$,and $C_3 = 2\,\mu F$ is charged by connecting $A$ and $B$ to a battery. Consider the following statements:
$I.$ Energy stored in $C_1$ $=$ Energy stored in $C_2$ $+$ Energy stored in $C_3$
$II.$ Charge on $C_1$ $=$ Charge on $C_2$ $+$ Charge on $C_3$
$III.$ Potential drop across $C_1$ $=$ Potential drop across $C_2$ $=$ Potential drop across $C_3$
Which of these is/are correct?

In the circuit shown,find $C$ if the effective capacitance of the whole circuit is to be $0.5\,\mu F.$ All values in the circuit are in $\mu F.$