The chemical formula of rust is:
- A$Fe_2O_3$
- B$FeO \cdot xH_2O$
- C$Fe_2O_3 \cdot xH_2O$
- D$Fe_3O_4 \cdot xH_2O$
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Given the half-cell reactions:
$2H^+ + \frac{1}{2}O_2 + 2e^- \to H_2O(l), E^o = 1.23 \ V$
$Fe^{2+} + 2e^- \to Fe(s), E^o = -0.44 \ V$
Calculate the value of $\Delta G^o$ in $kJ$ for the overall corrosion reaction.
$2H^+ + \frac{1}{2}O_2 + 2e^- \to H_2O(l), E^o = 1.23 \ V$
$Fe^{2+} + 2e^- \to Fe(s), E^o = -0.44 \ V$
Calculate the value of $\Delta G^o$ in $kJ$ for the overall corrosion reaction.
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