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(A) For a particle moving in a circular path with constant speed $v$,the acceleration is the centripetal acceleration,given by $a = v^2/r$.Since the p

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$2\pi v/T$

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(A) For a particle moving in a circular path with constant speed $v$,the acceleration is the centripetal acceleration,given by $a = v^2/r$.Since the particle completes one circle of circumference $2\pi r$ in time $T$,the speed is $v = (2\pi r)/T$.From this,we can write $r = (vT)/(2\pi)$.Substituting the value of $r$ into the acceleration formula: $a = v^2 / ((vT)/(2\pi)) = v^2 \cdot (2\pi) / (vT) = (2\pi v)/T$.Therefore,the acceleration of the particle is $(2\pi v)/T$.

$A$ particle moves with constant speed $v$ along a circular path of radius $r$ and completes the circle in time $T$. The acceleration of the particle is

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