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(A) The resultant dipole moment $(\mu)$ of a molecule depends on its symmetry and the polarity of its bonds.For para-substituted benzene derivatives,i

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$(iii) \& (iv)$ only

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(A) The resultant dipole moment $(\mu)$ of a molecule depends on its symmetry and the polarity of its bonds.For para-substituted benzene derivatives,if the two substituents are identical,the dipole moments of the two $C-X$ bonds are equal in magnitude and opposite in direction,leading to a net dipole moment of $\mu = 0$.$(i)$ $1,4-dichlorobenzene$: The two $C-Cl$ bond dipoles cancel each other out,so $\mu = 0$.(ii) $1,4-dicyanobenzene$ (terephthalonitrile): The two $C-CN$ bond dipoles cancel each other out,so $\mu = 0$.(iii) $1,4-dihydroxybenzene$ (hydroquinone): Due to the free rotation of the $-OH$ groups,the molecule can adopt conformations where the bond dipoles do not cancel,resulting in $\mu 
eq 0$.(iv) $1,4-dimercaptobenzene$ (benzene$-1,4-$dithiol): Similar to hydroquinone,the $-SH$ groups can rotate,leading to a non-zero resultant dipole moment,$\mu 
eq 0$.Therefore,molecules $(iii)$ and $(iv)$ have a resultant dipole moment $\mu 
eq 0$.

For which molecules among the following,the resultant dipole moment $(\mu) \neq 0?$

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