For two types of magnetic materials A and B,t | vedclass

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(A) $1$. For paramagnetic materials,according to Curie's Law,$\chi = \frac{C}{T}$,which implies $\frac{1}{\chi} = \frac{T}{C}$. This represents a stra

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$A$ is paramagnetic and $B$ is diamagnetic

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(A) $1$. For paramagnetic materials,according to Curie's Law,$\chi = \frac{C}{T}$,which implies $\frac{1}{\chi} = \frac{T}{C}$. This represents a straight line passing through the origin with a positive slope.$2$. For ferromagnetic materials above the Curie temperature $(T_c)$,the susceptibility follows the Curie-Weiss Law: $\chi = \frac{C}{T - T_c}$,which implies $\frac{1}{\chi} = \frac{T - T_c}{C}$. This represents a straight line with a positive slope that does not pass through the origin.$3$. For diamagnetic materials,the susceptibility $\chi$ is small,negative,and independent of temperature. Thus,$\frac{1}{\chi}$ is a constant negative value,resulting in a horizontal line (zero slope) in the $\frac{1}{\chi}$ vs $T$ graph.$4$. In the given figure,line $A$ passes through the origin with a positive slope,indicating it is paramagnetic. Line $B$ is a horizontal line (zero slope),indicating it is diamagnetic.$5$. Therefore,$A$ is paramagnetic and $B$ is diamagnetic.

For two types of magnetic materials $A$ and $B$,the variation of $\frac{1}{\chi}$ ($\chi$: magnetic susceptibility) versus temperature $T$ is shown in the figure. Then:

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