For the reduction of one molecule of CO_2 wit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The overall chemical equation for photosynthesis is $6CO_2 + 12H_2O \rightarrow C_6H_{12}O_6 + 6O_2 + 6H_2O$.The total energy required to reduce $

Vedclass · Accepted Answer

$110$

Vedclass · Answer

(B) The overall chemical equation for photosynthesis is $6CO_2 + 12H_2O \rightarrow C_6H_{12}O_6 + 6O_2 + 6H_2O$.The total energy required to reduce $6$ molecules of $CO_2$ to form one molecule of glucose is approximately $686$ $kcal$.To find the energy required for the reduction of one molecule of $CO_2$,we divide the total energy by $6$: $686 / 6 \approx 114.3$ $kcal$.Among the given options,$110$ $kcal$ is the closest approximation to the energy required for the reduction of one molecule of $CO_2$.

For the reduction of one molecule of $CO_2$ with water,the energy required is (in $kcal$)

Similar Questions

What are the two circuits for the installation of $CO_2$?

Select the incorrect statement $:$

Photosynthetic microorganisms ........... .

How do plants obtain their nutrition?

Vedclass Test Series

Exam Paper Generator

Online Exam Module