For the reaction: $H_{2} + I_{2} \longrightarrow 2 HI$,the differential rate law is

For the reaction $2N_2O_5(g) \rightleftharpoons 4NO_2(g) + O_2(g)$ in a closed vessel,the concentration of $NO_2$ increases by $2.0 \times 10^{-2} \ mol \ L^{-1}$ in $5 \ s$. Calculate the rate of change of concentration of $N_2O_5$.

The decomposition of $N_{2}O_{5}$ in $CCl_{4}$ at $318 \ K$ has been studied by monitoring the concentration of $N_{2}O_{5}$ in the solution. Initially the concentration of $N_{2}O_{5}$ is $2.33 \ mol \ L^{-1}$ and after $184 \ minutes$,it is reduced to $2.08 \ mol \ L^{-1}$. The reaction takes place according to the equation:
$2N_{2}O_{5(g)} \rightarrow 4NO_{2(g)} + O_{2(g)}$
Calculate the average rate of this reaction in terms of hours,minutes,and seconds. What is the rate of production of $NO_{2}$ during this period?

Select the correct reaction for the given rate: $\text{rate} = -\frac{1}{6} \frac{d[A]}{dt} = -\frac{1}{4} \frac{d[B]}{dt} = \frac{1}{3} \frac{d[C]}{dt} = \frac{1}{4} \frac{d[D]}{dt}$

Why is the rate of reaction expressed as negative with respect to a reactant? Is the rate of reaction really negative?

In a gaseous reaction $A_{2(g)} \longrightarrow B_{(g)} + \frac{1}{2} C_{(g)}$,the increase in pressure from $100 \text{ mm}$ to $120 \text{ mm}$ is noticed in $5 \text{ min}$. The rate of disappearance of $A_2$ in $\text{mm min}^{-1}$ is