For the reaction 5Br^-{_{text{(aq)}}} + 6H^+{ | vedclass

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Question

(C) For the given reaction: $5Br^-{_{	ext{(aq)}}} + 6H^+{_{	ext{(aq)}}} + BrO_3^-{_{	ext{(aq)}}} ightarrow 3Br_{2	ext{(aq)}} + 3H_2O_{	ext{(l)}

Vedclass · Accepted Answer

$0.03$

Vedclass · Answer

(C) For the given reaction: $5Br^-{_{	ext{(aq)}}} + 6H^+{_{	ext{(aq)}}} + BrO_3^-{_{	ext{(aq)}}} ightarrow 3Br_{2	ext{(aq)}} + 3H_2O_{	ext{(l)}}$
The rate of reaction expression is:
$Rate = -\frac{1}{5} \frac{\Delta[Br^{-}]}{\Delta t} = -\frac{\Delta[BrO_3^{-}]}{\Delta t} = +\frac{1}{3} \frac{\Delta[Br_2]}{\Delta t}$
Given that $-\frac{\Delta[BrO_3^{-}]}{\Delta t} = 0.01 \ mol \ L^{-1} \ min^{-1}$,we equate the terms:
$-\frac{\Delta[BrO_3^{-}]}{\Delta t} = \frac{1}{3} \frac{\Delta[Br_2]}{\Delta t}$
Substituting the given value:
$0.01 = \frac{1}{3} \frac{\Delta[Br_2]}{\Delta t}$
Therefore,$\frac{\Delta[Br_2]}{\Delta t} = 3 	imes 0.01 = 0.03 \ mol \ L^{-1} \ min^{-1}$.

For the reaction $5Br^-{_{\text{(aq)}}} + 6H^+{_{\text{(aq)}}} + BrO_3^-{_{\text{(aq)}}} \rightarrow 3Br_{2\text{(aq)}} + 3H_2O_{\text{(l)}}$. If $-\frac{\Delta[BrO_3^{-}]}{\Delta t} = 0.01 \ mol \ L^{-1} \ min^{-1}$,calculate $\frac{\Delta[Br_2]}{\Delta t}$ in $mol \ L^{-1} \ min^{-1}$.

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