For the reaction,C_3H_{8(g)} + 5O_{2(g)} long | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta U)$ is given by the equation: $\Delta H = \Delta U + \De

Vedclass · Accepted Answer

$-3RT$

Vedclass · Answer

(C) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta U)$ is given by the equation: $\Delta H = \Delta U + \Delta n_g RT$.Rearranging this equation,we get: $\Delta H - \Delta U = \Delta n_g RT$.For the given reaction: $C_3H_{8(g)} + 5O_{2(g)} \longrightarrow 3CO_{2(g)} + 4H_2O_{(l)}$.$\Delta n_g$ is the difference between the number of moles of gaseous products and gaseous reactants.$\Delta n_g = (n_{products, g}) - (n_{reactants, g}) = 3 - (1 + 5) = 3 - 6 = -3$.Substituting the value of $\Delta n_g$ into the equation: $\Delta H - \Delta U = -3RT$.

For the reaction,$C_3H_{8(g)} + 5O_{2(g)} \longrightarrow 3CO_{2(g)} + 4H_2O_{(l)}$ at constant temperature,$\Delta H - \Delta U$ is:

Similar Questions

$X$ is an extensive property and $x$ is an intensive property of a thermodynamic system. Which of the following statement$(s)$ is (are) correct?

The enthalpy of fusion of ice per mole is approximately $...$ $kJ / mol$.

If $5 \ mol$ of an ideal gas expands from $10 \ L$ to a volume of $100 \ L$ at $300 \ K$ under isothermal and reversible conditions,then the work done,$w$,is $-x \ J$. The value of $x$ is $ . . . . . . $. (Given $R = 8.314 \ J \ K^{-1} \ mol^{-1}$)

In an irreversible expansion of a gas,the work done by the gas is given by.....

Assume each reaction is carried out in an open container. For which reaction will $\Delta H = \Delta E$ ?

Vedclass Test Series

Exam Paper Generator

Online Exam Module